b^2-10b-90=0

Solution for b^2-10b-90=0 equation:

b^2-10b-90=0

a = 1; b = -10; c = -90;
Δ = b2-4ac
Δ = -102-4·1·(-90)
Δ = 460
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{460}=\sqrt{4*115}=\sqrt{4}*\sqrt{115}=2\sqrt{115}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{115}}{2*1}=\frac{10-2\sqrt{115}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{115}}{2*1}=\frac{10+2\sqrt{115}}{2}
$